3(g+1)=4(-6+g)

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Solution for 3(g+1)=4(-6+g) equation: 



3(g+1)=4(-6+g)

We move all terms to the left:

3(g+1)-(4(-6+g))=0

We add all the numbers together, and all the variables

3(g+1)-(4(g-6))=0

We multiply parentheses

3g-(4(g-6))+3=0



We calculate terms in parentheses: -(4(g-6)), so:

4(g-6)

We multiply parentheses

4g-24

Back to the equation:

-(4g-24)



We get rid of parentheses

3g-4g+24+3=0

We add all the numbers together, and all the variables

-1g+27=0

We move all terms containing g to the left, all other terms to the right

-g=-27

g=-27/-1

g=+27

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