3(f-5)=27

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Solution for 3(f-5)=27 equation: 



3(f-5)=27

We move all terms to the left:

3(f-5)-(27)=0

We multiply parentheses

3f-15-27=0

We add all the numbers together, and all the variables

3f-42=0

We move all terms containing f to the left, all other terms to the right

3f=42

f=42/3

f=14

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