3(f+4)=2-(f+2)

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Solution for 3(f+4)=2-(f+2) equation: 



3(f+4)=2-(f+2)

We move all terms to the left:

3(f+4)-(2-(f+2))=0

We multiply parentheses

3f-(2-(f+2))+12=0



We calculate terms in parentheses: -(2-(f+2)), so:

2-(f+2)

determiningTheFunctionDomain
-(f+2)+2

We get rid of parentheses

-f-2+2

We add all the numbers together, and all the variables

-f

Back to the equation:

-(-f)



We add all the numbers together, and all the variables

3f-(-1f)+12=0

We get rid of parentheses

3f+1f+12=0

We add all the numbers together, and all the variables

4f+12=0

We move all terms containing f to the left, all other terms to the right

4f=-12

f=-12/4

f=-3

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