3(f+20)=12(f-5)+f

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Solution for 3(f+20)=12(f-5)+f equation:


3(f+20)=12(f-5)+f

We simplify the equation to the form, which is simple to understand 
3(f+20)=12(f-5)+f

Reorder the terms in parentheses
+(+3f+60)=12*(f-5)+f

Remove unnecessary parentheses
+3f+60=+12+*(+f-5+)+f

Reorder the terms in parentheses
+3f+60=+(+12f-60)+f

Remove unnecessary parentheses
+3f+60=+12f-60+f

We move all terms containing f to the left and all other terms to the right. 
+3f-12f-1f=-60-60

We simplify left and right side of the equation. 
-10f=-120

We divide both sides of the equation by -10 to get f. 
f=12

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