3(f+2)+1=19

Solution for 3(f+2)+1=19 equation:

Simplifying
3(f + 2) + 1 = 19

Reorder the terms:
3(2 + f) + 1 = 19
(2 * 3 + f * 3) + 1 = 19
(6 + 3f) + 1 = 19

Reorder the terms:
6 + 1 + 3f = 19

Combine like terms: 6 + 1 = 7
7 + 3f = 19

Solving
7 + 3f = 19

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + 3f = 19 + -7

Combine like terms: 7 + -7 = 0
0 + 3f = 19 + -7
3f = 19 + -7

Combine like terms: 19 + -7 = 12
3f = 12

Divide each side by '3'.
f = 4

Simplifying
f = 4