3(f+1)=6-f

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Solution for 3(f+1)=6-f equation: 



3(f+1)=6-f

We move all terms to the left:

3(f+1)-(6-f)=0

We add all the numbers together, and all the variables

3(f+1)-(-1f+6)=0

We multiply parentheses

3f-(-1f+6)+3=0

We get rid of parentheses

3f+1f-6+3=0

We add all the numbers together, and all the variables

4f-3=0

We move all terms containing f to the left, all other terms to the right

4f=3

f=3/4

f=3/4

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