3(e+4)+5=35

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Solution for 3(e+4)+5=35 equation: 



3(e+4)+5=35

We move all terms to the left:

3(e+4)+5-(35)=0

We add all the numbers together, and all the variables

3(e+4)-30=0

We multiply parentheses

3e+12-30=0

We add all the numbers together, and all the variables

3e-18=0

We move all terms containing e to the left, all other terms to the right

3e=18

e=18/3

e=6

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