3(d-5)+12d=5(d-3)+

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Solution for 3(d-5)+12d=5(d-3)+ equation: 



3(d-5)+12d=5(d-3)+

We move all terms to the left:

3(d-5)+12d-(5(d-3)+)=0

We add all the numbers together, and all the variables

12d+3(d-5)-(5(d-3)+)=0

We multiply parentheses

12d+3d-(5(d-3)+)-15=0



We calculate terms in parentheses: -(5(d-3)+), so:

5(d-3)+

We add all the numbers together, and all the variables

5(d-3)

We multiply parentheses

5d-15

Back to the equation:

-(5d-15)



We add all the numbers together, and all the variables

15d-(5d-15)-15=0

We get rid of parentheses

15d-5d+15-15=0

We add all the numbers together, and all the variables

10d=0

d=0/10

d=0

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