3(d-5)+12=6

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Solution for 3(d-5)+12=6 equation: 



3(d-5)+12=6

We move all terms to the left:

3(d-5)+12-(6)=0

We add all the numbers together, and all the variables

3(d-5)+6=0

We multiply parentheses

3d-15+6=0

We add all the numbers together, and all the variables

3d-9=0

We move all terms containing d to the left, all other terms to the right

3d=9

d=9/3

d=3

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