3(d-2)=7d+11

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Solution for 3(d-2)=7d+11 equation: 



3(d-2)=7d+11

We move all terms to the left:

3(d-2)-(7d+11)=0

We multiply parentheses

3d-(7d+11)-6=0

We get rid of parentheses

3d-7d-11-6=0

We add all the numbers together, and all the variables

-4d-17=0

We move all terms containing d to the left, all other terms to the right

-4d=17

d=17/-4

d=-4+1/4

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