3(d-2)=5(d+5)

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Solution for 3(d-2)=5(d+5) equation: 



3(d-2)=5(d+5)

We move all terms to the left:

3(d-2)-(5(d+5))=0

We multiply parentheses

3d-(5(d+5))-6=0



We calculate terms in parentheses: -(5(d+5)), so:

5(d+5)

We multiply parentheses

5d+25

Back to the equation:

-(5d+25)



We get rid of parentheses

3d-5d-25-6=0

We add all the numbers together, and all the variables

-2d-31=0

We move all terms containing d to the left, all other terms to the right

-2d=31

d=31/-2

d=-15+1/2

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