3(d-2)+2(d+1)=

Solution for 3(d-2)+2(d+1)= equation:

Simplifying
3(d + -2) + 2(d + 1) = 0

Reorder the terms:
3(-2 + d) + 2(d + 1) = 0
(-2 * 3 + d * 3) + 2(d + 1) = 0
(-6 + 3d) + 2(d + 1) = 0

Reorder the terms:
-6 + 3d + 2(1 + d) = 0
-6 + 3d + (1 * 2 + d * 2) = 0
-6 + 3d + (2 + 2d) = 0

Reorder the terms:
-6 + 2 + 3d + 2d = 0

Combine like terms: -6 + 2 = -4
-4 + 3d + 2d = 0

Combine like terms: 3d + 2d = 5d
-4 + 5d = 0

Solving
-4 + 5d = 0

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 5d = 0 + 4

Combine like terms: -4 + 4 = 0
0 + 5d = 0 + 4
5d = 0 + 4

Combine like terms: 0 + 4 = 4
5d = 4

Divide each side by '5'.
d = 0.8

Simplifying
d = 0.8