3(d-10)+2(d-29)=2

Solution for 3(d-10)+2(d-29)=2 equation:

Simplifying
3(d + -10) + 2(d + -29) = 2

Reorder the terms:
3(-10 + d) + 2(d + -29) = 2
(-10 * 3 + d * 3) + 2(d + -29) = 2
(-30 + 3d) + 2(d + -29) = 2

Reorder the terms:
-30 + 3d + 2(-29 + d) = 2
-30 + 3d + (-29 * 2 + d * 2) = 2
-30 + 3d + (-58 + 2d) = 2

Reorder the terms:
-30 + -58 + 3d + 2d = 2

Combine like terms: -30 + -58 = -88
-88 + 3d + 2d = 2

Combine like terms: 3d + 2d = 5d
-88 + 5d = 2

Solving
-88 + 5d = 2

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '88' to each side of the equation.
-88 + 88 + 5d = 2 + 88

Combine like terms: -88 + 88 = 0
0 + 5d = 2 + 88
5d = 2 + 88

Combine like terms: 2 + 88 = 90
5d = 90

Divide each side by '5'.
d = 18

Simplifying
d = 18