3(d-1)+2=2(d+1)

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Solution for 3(d-1)+2=2(d+1) equation:


Simplifying
3(d + -1) + 2 = 2(d + 1)

Reorder the terms:
3(-1 + d) + 2 = 2(d + 1)
(-1 * 3 + d * 3) + 2 = 2(d + 1)
(-3 + 3d) + 2 = 2(d + 1)

Reorder the terms:
-3 + 2 + 3d = 2(d + 1)

Combine like terms: -3 + 2 = -1
-1 + 3d = 2(d + 1)

Reorder the terms:
-1 + 3d = 2(1 + d)
-1 + 3d = (1 * 2 + d * 2)
-1 + 3d = (2 + 2d)

Solving
-1 + 3d = 2 + 2d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-2d' to each side of the equation.
-1 + 3d + -2d = 2 + 2d + -2d

Combine like terms: 3d + -2d = 1d
-1 + 1d = 2 + 2d + -2d

Combine like terms: 2d + -2d = 0
-1 + 1d = 2 + 0
-1 + 1d = 2

Add '1' to each side of the equation.
-1 + 1 + 1d = 2 + 1

Combine like terms: -1 + 1 = 0
0 + 1d = 2 + 1
1d = 2 + 1

Combine like terms: 2 + 1 = 3
1d = 3

Divide each side by '1'.
d = 3

Simplifying
d = 3

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