3(d+3)+4(d+1)=15

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Solution for 3(d+3)+4(d+1)=15 equation:


Simplifying
3(d + 3) + 4(d + 1) = 15

Reorder the terms:
3(3 + d) + 4(d + 1) = 15
(3 * 3 + d * 3) + 4(d + 1) = 15
(9 + 3d) + 4(d + 1) = 15

Reorder the terms:
9 + 3d + 4(1 + d) = 15
9 + 3d + (1 * 4 + d * 4) = 15
9 + 3d + (4 + 4d) = 15

Reorder the terms:
9 + 4 + 3d + 4d = 15

Combine like terms: 9 + 4 = 13
13 + 3d + 4d = 15

Combine like terms: 3d + 4d = 7d
13 + 7d = 15

Solving
13 + 7d = 15

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-13' to each side of the equation.
13 + -13 + 7d = 15 + -13

Combine like terms: 13 + -13 = 0
0 + 7d = 15 + -13
7d = 15 + -13

Combine like terms: 15 + -13 = 2
7d = 2

Divide each side by '7'.
d = 0.2857142857

Simplifying
d = 0.2857142857

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