3(d+2m)=4(m+12)

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Solution for 3(d+2m)=4(m+12) equation:


Simplifying
3(d + 2m) = 4(m + 12)
(d * 3 + 2m * 3) = 4(m + 12)
(3d + 6m) = 4(m + 12)

Reorder the terms:
3d + 6m = 4(12 + m)
3d + 6m = (12 * 4 + m * 4)
3d + 6m = (48 + 4m)

Solving
3d + 6m = 48 + 4m

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-6m' to each side of the equation.
3d + 6m + -6m = 48 + 4m + -6m

Combine like terms: 6m + -6m = 0
3d + 0 = 48 + 4m + -6m
3d = 48 + 4m + -6m

Combine like terms: 4m + -6m = -2m
3d = 48 + -2m

Divide each side by '3'.
d = 16 + -0.6666666667m

Simplifying
d = 16 + -0.6666666667m

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