3(d+2)=3d+6=

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Solution for 3(d+2)=3d+6= equation: 



3(d+2)=3d+6=

We move all terms to the left:

3(d+2)-(3d+6)=0

We multiply parentheses

3d-(3d+6)+6=0

We get rid of parentheses

3d-3d-6+6=0

We add all the numbers together, and all the variables

=0

d=0/1

d=0

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