3(d+2)+5=17

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Solution for 3(d+2)+5=17 equation: 



3(d+2)+5=17

We move all terms to the left:

3(d+2)+5-(17)=0

We add all the numbers together, and all the variables

3(d+2)-12=0

We multiply parentheses

3d+6-12=0

We add all the numbers together, and all the variables

3d-6=0

We move all terms containing d to the left, all other terms to the right

3d=6

d=6/3

d=2

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