3(d+1)=2(3d-9)

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Solution for 3(d+1)=2(3d-9) equation:


Simplifying
3(d + 1) = 2(3d + -9)

Reorder the terms:
3(1 + d) = 2(3d + -9)
(1 * 3 + d * 3) = 2(3d + -9)
(3 + 3d) = 2(3d + -9)

Reorder the terms:
3 + 3d = 2(-9 + 3d)
3 + 3d = (-9 * 2 + 3d * 2)
3 + 3d = (-18 + 6d)

Solving
3 + 3d = -18 + 6d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-6d' to each side of the equation.
3 + 3d + -6d = -18 + 6d + -6d

Combine like terms: 3d + -6d = -3d
3 + -3d = -18 + 6d + -6d

Combine like terms: 6d + -6d = 0
3 + -3d = -18 + 0
3 + -3d = -18

Add '-3' to each side of the equation.
3 + -3 + -3d = -18 + -3

Combine like terms: 3 + -3 = 0
0 + -3d = -18 + -3
-3d = -18 + -3

Combine like terms: -18 + -3 = -21
-3d = -21

Divide each side by '-3'.
d = 7

Simplifying
d = 7

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