3(c-8)+6(c-12)=12

Solution for 3(c-8)+6(c-12)=12 equation:

Simplifying
3(c + -8) + 6(c + -12) = 12

Reorder the terms:
3(-8 + c) + 6(c + -12) = 12
(-8 * 3 + c * 3) + 6(c + -12) = 12
(-24 + 3c) + 6(c + -12) = 12

Reorder the terms:
-24 + 3c + 6(-12 + c) = 12
-24 + 3c + (-12 * 6 + c * 6) = 12
-24 + 3c + (-72 + 6c) = 12

Reorder the terms:
-24 + -72 + 3c + 6c = 12

Combine like terms: -24 + -72 = -96
-96 + 3c + 6c = 12

Combine like terms: 3c + 6c = 9c
-96 + 9c = 12

Solving
-96 + 9c = 12

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '96' to each side of the equation.
-96 + 96 + 9c = 12 + 96

Combine like terms: -96 + 96 = 0
0 + 9c = 12 + 96
9c = 12 + 96

Combine like terms: 12 + 96 = 108
9c = 108

Divide each side by '9'.
c = 12

Simplifying
c = 12