3(c-7)=-5(2c-5)

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Solution for 3(c-7)=-5(2c-5) equation: 



3(c-7)=-5(2c-5)

We move all terms to the left:

3(c-7)-(-5(2c-5))=0

We multiply parentheses

3c-(-5(2c-5))-21=0



We calculate terms in parentheses: -(-5(2c-5)), so:

-5(2c-5)

We multiply parentheses

-10c+25

Back to the equation:

-(-10c+25)



We get rid of parentheses

3c+10c-25-21=0

We add all the numbers together, and all the variables

13c-46=0

We move all terms containing c to the left, all other terms to the right

13c=46

c=46/13

c=3+7/13

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