3(c-6)=3(3c+10)

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Solution for 3(c-6)=3(3c+10) equation: 



3(c-6)=3(3c+10)

We move all terms to the left:

3(c-6)-(3(3c+10))=0

We multiply parentheses

3c-(3(3c+10))-18=0



We calculate terms in parentheses: -(3(3c+10)), so:

3(3c+10)

We multiply parentheses

9c+30

Back to the equation:

-(9c+30)



We get rid of parentheses

3c-9c-30-18=0

We add all the numbers together, and all the variables

-6c-48=0

We move all terms containing c to the left, all other terms to the right

-6c=48

c=48/-6

c=-8

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