3(c-5)=2(c-10)

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Solution for 3(c-5)=2(c-10) equation: 



3(c-5)=2(c-10)

We move all terms to the left:

3(c-5)-(2(c-10))=0

We multiply parentheses

3c-(2(c-10))-15=0



We calculate terms in parentheses: -(2(c-10)), so:

2(c-10)

We multiply parentheses

2c-20

Back to the equation:

-(2c-20)



We get rid of parentheses

3c-2c+20-15=0

We add all the numbers together, and all the variables

c+5=0

We move all terms containing c to the left, all other terms to the right

c=-5

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