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3(c-5)-2c=10+c
We move all terms to the left:
3(c-5)-2c-(10+c)=0
We add all the numbers together, and all the variables
3(c-5)-2c-(c+10)=0
We add all the numbers together, and all the variables
-2c+3(c-5)-(c+10)=0
We multiply parentheses
-2c+3c-(c+10)-15=0
We get rid of parentheses
-2c+3c-c-10-15=0
We add all the numbers together, and all the variables
-25!=0
There is no solution for this equation
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