3(c-4)=4c-28

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Solution for 3(c-4)=4c-28 equation:


Simplifying
3(c + -4) = 4c + -28

Reorder the terms:
3(-4 + c) = 4c + -28
(-4 * 3 + c * 3) = 4c + -28
(-12 + 3c) = 4c + -28

Reorder the terms:
-12 + 3c = -28 + 4c

Solving
-12 + 3c = -28 + 4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4c' to each side of the equation.
-12 + 3c + -4c = -28 + 4c + -4c

Combine like terms: 3c + -4c = -1c
-12 + -1c = -28 + 4c + -4c

Combine like terms: 4c + -4c = 0
-12 + -1c = -28 + 0
-12 + -1c = -28

Add '12' to each side of the equation.
-12 + 12 + -1c = -28 + 12

Combine like terms: -12 + 12 = 0
0 + -1c = -28 + 12
-1c = -28 + 12

Combine like terms: -28 + 12 = -16
-1c = -16

Divide each side by '-1'.
c = 16

Simplifying
c = 16

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