3(c-4)-(8-4c)=-20

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Solution for 3(c-4)-(8-4c)=-20 equation: 



3(c-4)-(8-4c)=-20

We move all terms to the left:

3(c-4)-(8-4c)-(-20)=0

We add all the numbers together, and all the variables

3(c-4)-(-4c+8)-(-20)=0

We add all the numbers together, and all the variables

3(c-4)-(-4c+8)+20=0

We multiply parentheses

3c-(-4c+8)-12+20=0

We get rid of parentheses

3c+4c-8-12+20=0

We add all the numbers together, and all the variables

7c=0

c=0/7

c=0

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