3(c-4)+4=3+c-11

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Solution for 3(c-4)+4=3+c-11 equation: 



3(c-4)+4=3+c-11

We move all terms to the left:

3(c-4)+4-(3+c-11)=0

We add all the numbers together, and all the variables

3(c-4)-(c-8)+4=0

We multiply parentheses

3c-(c-8)-12+4=0

We get rid of parentheses

3c-c+8-12+4=0

We add all the numbers together, and all the variables

2c=0

c=0/2

c=0

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