3(c-2)=4(c-1)

Solution for 3(c-2)=4(c-1) equation:

Simplifying
3(c + -2) = 4(c + -1)

Reorder the terms:
3(-2 + c) = 4(c + -1)
(-2 * 3 + c * 3) = 4(c + -1)
(-6 + 3c) = 4(c + -1)

Reorder the terms:
-6 + 3c = 4(-1 + c)
-6 + 3c = (-1 * 4 + c * 4)
-6 + 3c = (-4 + 4c)

Solving
-6 + 3c = -4 + 4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4c' to each side of the equation.
-6 + 3c + -4c = -4 + 4c + -4c

Combine like terms: 3c + -4c = -1c
-6 + -1c = -4 + 4c + -4c

Combine like terms: 4c + -4c = 0
-6 + -1c = -4 + 0
-6 + -1c = -4

Add '6' to each side of the equation.
-6 + 6 + -1c = -4 + 6

Combine like terms: -6 + 6 = 0
0 + -1c = -4 + 6
-1c = -4 + 6

Combine like terms: -4 + 6 = 2
-1c = 2

Divide each side by '-1'.
c = -2

Simplifying
c = -2