3(c-2)=2(c+3)=

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Solution for 3(c-2)=2(c+3)= equation: 



3(c-2)=2(c+3)=

We move all terms to the left:

3(c-2)-(2(c+3))=0

We multiply parentheses

3c-(2(c+3))-6=0



We calculate terms in parentheses: -(2(c+3)), so:

2(c+3)

We multiply parentheses

2c+6

Back to the equation:

-(2c+6)



We get rid of parentheses

3c-2c-6-6=0

We add all the numbers together, and all the variables

c-12=0

We move all terms containing c to the left, all other terms to the right

c=12

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