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3(c-1)+2(3c+1)=-3c+1)
We move all terms to the left:
3(c-1)+2(3c+1)-(-3c+1))=0
We multiply parentheses
3c+6c-(-3c+1))-3+2=0
We add all the numbers together, and all the variables
9c-(-3c+1))-3+2=0
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