3(c-1)+2(3c+1)=-(c+1)

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Solution for 3(c-1)+2(3c+1)=-(c+1) equation:



3(c-1)+2(3c+1)=-(c+1)
We move all terms to the left:
3(c-1)+2(3c+1)-(-(c+1))=0
We multiply parentheses
3c+6c-(-(c+1))-3+2=0
We calculate terms in parentheses: -(-(c+1)), so:
-(c+1)
We get rid of parentheses
-c-1
We add all the numbers together, and all the variables
-1c-1
Back to the equation:
-(-1c-1)
We add all the numbers together, and all the variables
9c-(-1c-1)-1=0
We get rid of parentheses
9c+1c+1-1=0
We add all the numbers together, and all the variables
10c=0
c=0/10
c=0

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