3(c-1)+2(3c+1)=-(3c-1)

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Solution for 3(c-1)+2(3c+1)=-(3c-1) equation: 



3(c-1)+2(3c+1)=-(3c-1)

We move all terms to the left:

3(c-1)+2(3c+1)-(-(3c-1))=0

We multiply parentheses

3c+6c-(-(3c-1))-3+2=0



We calculate terms in parentheses: -(-(3c-1)), so:

-(3c-1)

We get rid of parentheses

-3c+1

Back to the equation:

-(-3c+1)



We add all the numbers together, and all the variables

9c-(-3c+1)-1=0

We get rid of parentheses

9c+3c-1-1=0

We add all the numbers together, and all the variables

12c-2=0

We move all terms containing c to the left, all other terms to the right

12c=2

c=2/12

c=1/6

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