3(c-1)+2(3c+1)=-(3c+1)+

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Solution for 3(c-1)+2(3c+1)=-(3c+1)+ equation: 



3(c-1)+2(3c+1)=-(3c+1)+

We move all terms to the left:

3(c-1)+2(3c+1)-(-(3c+1)+)=0

We multiply parentheses

3c+6c-(-(3c+1)+)-3+2=0



We calculate terms in parentheses: -(-(3c+1)+), so:

-(3c+1)+

We add all the numbers together, and all the variables

-(3c+1)

We get rid of parentheses

-3c-1

Back to the equation:

-(-3c-1)



We add all the numbers together, and all the variables

9c-(-3c-1)-1=0

We get rid of parentheses

9c+3c+1-1=0

We add all the numbers together, and all the variables

12c=0

c=0/12

c=0

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