3(c+4)-2=17

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Solution for 3(c+4)-2=17 equation: 



3(c+4)-2=17

We move all terms to the left:

3(c+4)-2-(17)=0

We add all the numbers together, and all the variables

3(c+4)-19=0

We multiply parentheses

3c+12-19=0

We add all the numbers together, and all the variables

3c-7=0

We move all terms containing c to the left, all other terms to the right

3c=7

c=7/3

c=2+1/3

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