3(c+3)=2(2c+2)

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Solution for 3(c+3)=2(2c+2) equation:


Simplifying
3(c + 3) = 2(2c + 2)

Reorder the terms:
3(3 + c) = 2(2c + 2)
(3 * 3 + c * 3) = 2(2c + 2)
(9 + 3c) = 2(2c + 2)

Reorder the terms:
9 + 3c = 2(2 + 2c)
9 + 3c = (2 * 2 + 2c * 2)
9 + 3c = (4 + 4c)

Solving
9 + 3c = 4 + 4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4c' to each side of the equation.
9 + 3c + -4c = 4 + 4c + -4c

Combine like terms: 3c + -4c = -1c
9 + -1c = 4 + 4c + -4c

Combine like terms: 4c + -4c = 0
9 + -1c = 4 + 0
9 + -1c = 4

Add '-9' to each side of the equation.
9 + -9 + -1c = 4 + -9

Combine like terms: 9 + -9 = 0
0 + -1c = 4 + -9
-1c = 4 + -9

Combine like terms: 4 + -9 = -5
-1c = -5

Divide each side by '-1'.
c = 5

Simplifying
c = 5

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