3(c+2c+1)=9c+3

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Solution for 3(c+2c+1)=9c+3 equation:


Simplifying
3(c + 2c + 1) = 9c + 3

Reorder the terms:
3(1 + c + 2c) = 9c + 3

Combine like terms: c + 2c = 3c
3(1 + 3c) = 9c + 3
(1 * 3 + 3c * 3) = 9c + 3
(3 + 9c) = 9c + 3

Reorder the terms:
3 + 9c = 3 + 9c

Add '-3' to each side of the equation.
3 + -3 + 9c = 3 + -3 + 9c

Combine like terms: 3 + -3 = 0
0 + 9c = 3 + -3 + 9c
9c = 3 + -3 + 9c

Combine like terms: 3 + -3 = 0
9c = 0 + 9c
9c = 9c

Add '-9c' to each side of the equation.
9c + -9c = 9c + -9c

Combine like terms: 9c + -9c = 0
0 = 9c + -9c

Combine like terms: 9c + -9c = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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