3(c+2)=5(2-c)

Solution for 3(c+2)=5(2-c) equation:

Simplifying
3(c + 2) = 5(2 + -1c)

Reorder the terms:
3(2 + c) = 5(2 + -1c)
(2 * 3 + c * 3) = 5(2 + -1c)
(6 + 3c) = 5(2 + -1c)
6 + 3c = (2 * 5 + -1c * 5)
6 + 3c = (10 + -5c)

Solving
6 + 3c = 10 + -5c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '5c' to each side of the equation.
6 + 3c + 5c = 10 + -5c + 5c

Combine like terms: 3c + 5c = 8c
6 + 8c = 10 + -5c + 5c

Combine like terms: -5c + 5c = 0
6 + 8c = 10 + 0
6 + 8c = 10

Add '-6' to each side of the equation.
6 + -6 + 8c = 10 + -6

Combine like terms: 6 + -6 = 0
0 + 8c = 10 + -6
8c = 10 + -6

Combine like terms: 10 + -6 = 4
8c = 4

Divide each side by '8'.
c = 0.5

Simplifying
c = 0.5