3(c+2)=4(2c-1)

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Solution for 3(c+2)=4(2c-1) equation: 



3(c+2)=4(2c-1)

We move all terms to the left:

3(c+2)-(4(2c-1))=0

We multiply parentheses

3c-(4(2c-1))+6=0



We calculate terms in parentheses: -(4(2c-1)), so:

4(2c-1)

We multiply parentheses

8c-4

Back to the equation:

-(8c-4)



We get rid of parentheses

3c-8c+4+6=0

We add all the numbers together, and all the variables

-5c+10=0

We move all terms containing c to the left, all other terms to the right

-5c=-10

c=-10/-5

c=+2

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