3(c+2)=3c+6

Solution for 3(c+2)=3c+6 equation:

Simplifying
3(c + 2) = 3c + 6

Reorder the terms:
3(2 + c) = 3c + 6
(2 * 3 + c * 3) = 3c + 6
(6 + 3c) = 3c + 6

Reorder the terms:
6 + 3c = 6 + 3c

Add '-6' to each side of the equation.
6 + -6 + 3c = 6 + -6 + 3c

Combine like terms: 6 + -6 = 0
0 + 3c = 6 + -6 + 3c
3c = 6 + -6 + 3c

Combine like terms: 6 + -6 = 0
3c = 0 + 3c
3c = 3c

Add '-3c' to each side of the equation.
3c + -3c = 3c + -3c

Combine like terms: 3c + -3c = 0
0 = 3c + -3c

Combine like terms: 3c + -3c = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.