3(c+2)=1+2c

Solution for 3(c+2)=1+2c equation:

Simplifying
3(c + 2) = 1 + 2c

Reorder the terms:
3(2 + c) = 1 + 2c
(2 * 3 + c * 3) = 1 + 2c
(6 + 3c) = 1 + 2c

Solving
6 + 3c = 1 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
6 + 3c + -2c = 1 + 2c + -2c

Combine like terms: 3c + -2c = 1c
6 + 1c = 1 + 2c + -2c

Combine like terms: 2c + -2c = 0
6 + 1c = 1 + 0
6 + 1c = 1

Add '-6' to each side of the equation.
6 + -6 + 1c = 1 + -6

Combine like terms: 6 + -6 = 0
0 + 1c = 1 + -6
1c = 1 + -6

Combine like terms: 1 + -6 = -5
1c = -5

Divide each side by '1'.
c = -5

Simplifying
c = -5