3(c+2)+4(c+1)=

Solution for 3(c+2)+4(c+1)= equation:

Simplifying
3(c + 2) + 4(c + 1) = 0

Reorder the terms:
3(2 + c) + 4(c + 1) = 0
(2 * 3 + c * 3) + 4(c + 1) = 0
(6 + 3c) + 4(c + 1) = 0

Reorder the terms:
6 + 3c + 4(1 + c) = 0
6 + 3c + (1 * 4 + c * 4) = 0
6 + 3c + (4 + 4c) = 0

Reorder the terms:
6 + 4 + 3c + 4c = 0

Combine like terms: 6 + 4 = 10
10 + 3c + 4c = 0

Combine like terms: 3c + 4c = 7c
10 + 7c = 0

Solving
10 + 7c = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + 7c = 0 + -10

Combine like terms: 10 + -10 = 0
0 + 7c = 0 + -10
7c = 0 + -10

Combine like terms: 0 + -10 = -10
7c = -10

Divide each side by '7'.
c = -1.428571429

Simplifying
c = -1.428571429