3(c+1)=2(x+1)+2y

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Solution for 3(c+1)=2(x+1)+2y equation:


Simplifying
3(c + 1) = 2(x + 1) + 2y

Reorder the terms:
3(1 + c) = 2(x + 1) + 2y
(1 * 3 + c * 3) = 2(x + 1) + 2y
(3 + 3c) = 2(x + 1) + 2y

Reorder the terms:
3 + 3c = 2(1 + x) + 2y
3 + 3c = (1 * 2 + x * 2) + 2y
3 + 3c = (2 + 2x) + 2y

Solving
3 + 3c = 2 + 2x + 2y

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 3c = 2 + 2x + -3 + 2y

Combine like terms: 3 + -3 = 0
0 + 3c = 2 + 2x + -3 + 2y
3c = 2 + 2x + -3 + 2y

Reorder the terms:
3c = 2 + -3 + 2x + 2y

Combine like terms: 2 + -3 = -1
3c = -1 + 2x + 2y

Divide each side by '3'.
c = -0.3333333333 + 0.6666666667x + 0.6666666667y

Simplifying
c = -0.3333333333 + 0.6666666667x + 0.6666666667y

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