3(c+1)-7=2

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Solution for 3(c+1)-7=2 equation: 



3(c+1)-7=2

We move all terms to the left:

3(c+1)-7-(2)=0

We add all the numbers together, and all the variables

3(c+1)-9=0

We multiply parentheses

3c+3-9=0

We add all the numbers together, and all the variables

3c-6=0

We move all terms containing c to the left, all other terms to the right

3c=6

c=6/3

c=2

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