3(c+1)+9=4(c-3)-c

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Solution for 3(c+1)+9=4(c-3)-c equation: 



3(c+1)+9=4(c-3)-c

We move all terms to the left:

3(c+1)+9-(4(c-3)-c)=0

We multiply parentheses

3c-(4(c-3)-c)+3+9=0



We calculate terms in parentheses: -(4(c-3)-c), so:

4(c-3)-c

We add all the numbers together, and all the variables

-1c+4(c-3)

We multiply parentheses

-1c+4c-12

We add all the numbers together, and all the variables

3c-12

Back to the equation:

-(3c-12)



We add all the numbers together, and all the variables

3c-(3c-12)+12=0

We get rid of parentheses

3c-3c+12+12=0

We add all the numbers together, and all the variables

24!=0

There is no solution for this equation

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