3(c+1)+2(3c+1)=(3c+1)

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Solution for 3(c+1)+2(3c+1)=(3c+1) equation: 



3(c+1)+2(3c+1)=(3c+1)

We move all terms to the left:

3(c+1)+2(3c+1)-((3c+1))=0

We multiply parentheses

3c+6c-((3c+1))+3+2=0



We calculate terms in parentheses: -((3c+1)), so:

(3c+1)

We get rid of parentheses

3c+1

Back to the equation:

-(3c+1)



We add all the numbers together, and all the variables

9c-(3c+1)+5=0

We get rid of parentheses

9c-3c-1+5=0

We add all the numbers together, and all the variables

6c+4=0

We move all terms containing c to the left, all other terms to the right

6c=-4

c=-4/6

c=-2/3

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