3(b-7)=48

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Solution for 3(b-7)=48 equation: 



3(b-7)=48

We move all terms to the left:

3(b-7)-(48)=0

We multiply parentheses

3b-21-48=0

We add all the numbers together, and all the variables

3b-69=0

We move all terms containing b to the left, all other terms to the right

3b=69

b=69/3

b=23

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