3(b-6)-3=7(10b-3)

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Solution for 3(b-6)-3=7(10b-3) equation: 



3(b-6)-3=7(10b-3)

We move all terms to the left:

3(b-6)-3-(7(10b-3))=0

We multiply parentheses

3b-(7(10b-3))-18-3=0



We calculate terms in parentheses: -(7(10b-3)), so:

7(10b-3)

We multiply parentheses

70b-21

Back to the equation:

-(70b-21)



We add all the numbers together, and all the variables

3b-(70b-21)-21=0

We get rid of parentheses

3b-70b+21-21=0

We add all the numbers together, and all the variables

-67b=0

b=0/-67

b=0

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