3(b-6)+2=14

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Solution for 3(b-6)+2=14 equation: 



3(b-6)+2=14

We move all terms to the left:

3(b-6)+2-(14)=0

We add all the numbers together, and all the variables

3(b-6)-12=0

We multiply parentheses

3b-18-12=0

We add all the numbers together, and all the variables

3b-30=0

We move all terms containing b to the left, all other terms to the right

3b=30

b=30/3

b=10

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