3(b-5)=4(b+2)

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Solution for 3(b-5)=4(b+2) equation:


Simplifying
3(b + -5) = 4(b + 2)

Reorder the terms:
3(-5 + b) = 4(b + 2)
(-5 * 3 + b * 3) = 4(b + 2)
(-15 + 3b) = 4(b + 2)

Reorder the terms:
-15 + 3b = 4(2 + b)
-15 + 3b = (2 * 4 + b * 4)
-15 + 3b = (8 + 4b)

Solving
-15 + 3b = 8 + 4b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-4b' to each side of the equation.
-15 + 3b + -4b = 8 + 4b + -4b

Combine like terms: 3b + -4b = -1b
-15 + -1b = 8 + 4b + -4b

Combine like terms: 4b + -4b = 0
-15 + -1b = 8 + 0
-15 + -1b = 8

Add '15' to each side of the equation.
-15 + 15 + -1b = 8 + 15

Combine like terms: -15 + 15 = 0
0 + -1b = 8 + 15
-1b = 8 + 15

Combine like terms: 8 + 15 = 23
-1b = 23

Divide each side by '-1'.
b = -23

Simplifying
b = -23

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