3(b-5)/2=-6

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Solution for 3(b-5)/2=-6 equation: 



3(b-5)/2=-6

We move all terms to the left:

3(b-5)/2-(-6)=0

We add all the numbers together, and all the variables

3(b-5)/2+6=0

We multiply all the terms by the denominator


3(b-5)+6*2=0

We add all the numbers together, and all the variables

3(b-5)+12=0

We multiply parentheses

3b-15+12=0

We add all the numbers together, and all the variables

3b-3=0

We move all terms containing b to the left, all other terms to the right

3b=3

b=3/3

b=1

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